IBM DB2 9.7 SQL Procedure Developer - 000-545 Exam Practice Test

A. CREATE PROCEDURE myschema.proc1(IN p1 INTEGER, OUT p2 CHAR(4), OUT p3
CHAR(4))
BEGIN
SET p2 = 'abc';
END

B. CREATE PROCEDURE myschema.proc1(IN p1 NUMBER, OUT p2 NUMBER, OUT p3 NUMBER) BEGIN SET p2 = 'abc'; END

C. CREATE PROCEDURE myschema.proc1(IN p1 CHAR(4), OUT p2 INTEGER, OUT p3
SMALLINT)
BEGIN
SET p2 = 123;
END

D. CREATE PROCEDURE otherschema.proc1(IN p1 CHAR(4), OUT p2 CHAR(4), OUT p3 CHAR(4)) BEGIN SET p2 = 'abc'; END

E. CREATE PROCEDURE myschema.proc1(IN p1 CHAR(4), OUT p2 INTEGER)
BEGIN
SET p2 = 123;
END

A. CREATE PROCEDURE update_count4 (IN tab_name VARCHAR(128), IN col_name1
VARCHAR(128), IN col_name2 VARCHAR(128), IN
new_count INTEGER, IN item_code INTEGER)
BEGIN
DECLARE v_dynSQL VARCHAR(200);
SET v_dynSQL = 'UPDATE ? SET ?=? WHERE ?=?';
PREPARE v_stmt1 FROM v_dynSQL;
EXECUTE v_stmt1 USING tab_name, col_name1, new_count, col_name2, item_code;
END

B. CREATE PROCEDURE update_count2 (IN tab_name VARCHAR(128), IN new_count
INTEGER, IN item_code INTEGER)
BEGIN
DECLARE v_dynSQL VARCHAR(200);
SET v_dynSQL = 'UPDATE ? SET quantity_on_hand=? WHERE item_number=?';
PREPARE v_stmt1 FROM v_dynSQL;
EXECUTE v_stmt1 USING tab_name, new_count, item_code;
END

C. CREATE PROCEDURE update_count5 (IN new_count INTEGER, IN item_code INTEGER)
BEGIN
DECLARE v_dynSQL VARCHAR(200);
DECLARE v_col_name VARCHAR(128);
SET v_col_name = 'item_number';
SET v_dynSQL = 'UPDATE stock SET quantity_on_hand=? WHERE ?=?';
PREPARE v_stmt1 FROM v_dynSQL;
EXECUTE v_stmt1 USING new_count, v_col_name, item_code;
END

D. CREATE PROCEDURE update_count1 (IN new_count INTEGER, IN item_code INTEGER)
BEGIN
DECLARE v_dynSQL VARCHAR(200);
SET v_dynSQL = 'UPDATE stock SET quantity_on_hand=? WHERE item_number=?';
PREPARE v_stmt1 FROM v_dynSQL;
EXECUTE v_stmt1 USING new_count, item_code;
END

A. variable, cursor, condition, handler

B. variable, condition, handler, cursor

C. variable, cursor, handler, condition

D. variable, condition, cursor, handler

A. to eliminate the need for testing

B. to reduce code sharing

C. to move business logic rules into the database

D. to use different programming languages

A. 123, 123

B. 100, 100

C. 100 , 1

D. 100, 0

A. CREATE ARRAY names AS VARCHAR(25);

B. CREATE TYPE names[30] VARCHAR(25);

C. CREATE ARRAY names[30] VARCHAR(25);

D. CREATE TYPE names AS VARCHAR(25) ARRAY[30];

A. 500

B. 5500

C. 1000

D. 5200

A. 2

B. 4

C. 3

D. 1

A. SET c2 = c1;

B. SET c1 = CURSOR FOR VALUES ('a', 'b', 'c');

C. IF (c1 = c2) THEN ?END;

D. SET c1 = CURSOR FOR SELECT * FROM t;