IBM WebSphere Application Server Network Deployment V8.0, Core Administration - C2180-317 Exam Practice Test
A system administrator is creating a new WebSphere cell consisting of three dedicated machines: ?web server ?deployment manager ?application server node To provide process level failover, the administrator should create a cluster with:
Correct Answer: D
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A system administrator is using the debug features of the IBM Assembly and Deploy Tools (IADT) to resolve an error in a wsadmin Jython script. Which control on the Debug view can the administrator use to progress through the statements without redirecting to any encountered functions?
Correct Answer: A
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While monitoring a JDBC data source's performance during a test load, a system administrator notices that there are a large number of prepared statements discarded from the cache. In order to improve application throughput, how should the administrator tune the data source?
Correct Answer: B
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A system administrator needs to install the IBM Installation Manager for WebSphere Application Server Network Deployment V8.0 using a non-root account. What step must the administrator take so that the installation can be managed by two different non-root user accounts? Install the IBM Installation Manager:
Correct Answer: C
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A Java EE application is deployed to a horizontal cluster and makes use of HTTP session objects. The administrator is required to ensure failover of these session objects, and chooses to implement memory-to-memory replication. To maximize chances of successful failover, how should the administrator configure the replication?
Correct Answer: C
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A system administrator needs to backup a WebSphere Application Server profile without disrupting normal operations.
How can the administrator accomplish this?
How can the administrator accomplish this?
Correct Answer: D
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A system administrator must configure IBM WebSphere Application Server Network Deployment V8.0 to authenticate users with a Windows domain. The administrator should configure a registry that is:
Correct Answer: C
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