Latest Nov-2021 Oracle 1z0-071 Dumps Updated 305 Questions
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NEW QUESTION 122
View the exhibit and examine the description of the DEPARTMENTS and EMPLOYEES tables.
You wrote this SQL statement to retrieve EMPLOYEE_ID, FIRST_NAME, and DEPARTMENT NAME, for all employees:
SELECT employee_id, first_name, department_name
FROM employees
NATURAL JOIN departments;
The desired output is not obtained after executing the above SQL statement. What could be the reason for this?
- A. The EMPLOYEES and DEPARTMENTS tables have more than one column with the same column name and data type.
Natural join needs only one column to be the same in each table. The EMPLOYEES and DEPARTMENTS tables have two columns that are the same (Department_ID and Manager_ID) - B. The NATURAL JOIN clause is missing the USING clause.
- C. The table prefix is missing for the column names in the SELECT clause.
- D. The DEPARTMENTS table is not used before the EMPLOYEES table in the FROM clause.
Answer: A
NEW QUESTION 123
Which three actions can you perform by using the ALTER TABLE command?
- A. Lock a set of rows in a table.
- B. Rename a table.
- C. Drop all columns simultaneously from a table.
- D. Drop pseudocolumns from a table.
- E. Restrict all DML statements on a table.
- F. Enable or disable constraints on a table.
Answer: B,C,F
NEW QUESTION 124
View the exhibit and examine the description of the EMPLOYEES table. (Choose two.)
You executed this SQL statement:
SELECT first_name, department_id, salary
FROM employees
ORDER BY department_id, first_name, salary desc;
Which two statements are true regarding the result? (Choose two.)
- A. The values in the FIRST_NAME column would be returned in ascending order for all employees having the same value in the DEPARTMENT_ID column.
- B. The values in the SALARY column would be returned in descending order for all employees having the same value in the DEPARTMENT_ID column.
- C. The values in the SALARY column would be returned in descending order for all employees having the same value in the DEPARTMENT_ID and FIRST_NAME column.
- D. The values in all columns would be returned in descending order.
- E. The values in the FIRST_NAME column would be returned in descending order for all employees having the same value in the DEPARTMENT_ID column.
Answer: A,C
NEW QUESTION 125
You have the privileges to create any type of synonym.
Which statement will create a synonym called EMPfor the HCM.EMPLOYEE_RECORDS table that is accessible to all users?
- A. CREATE PUBLIC SYNONIM emp FOR hcm.employee_records;
- B. CREATE SYNONIM emp FOR hcm.employee_records;
- C. CREATE GLOBAL SYNONIM emp FOR hcm.employee_records;
- D. CREATE SYNONIM SYS.emp FOR hcm.employee_records;
- E. CREATE SYNONIM PUBLIC.emp FOR hcm.employee_records;
Answer: A
Explanation:
CREATE PUBLIC SYNONYM emp_table
Reference: https://docs.oracle.com/database/121/SQLRF/statements_7001.htm#SQLRF01401
NEW QUESTION 126
Examine the structure of the BOOKS_TRANSACTIONS table:
NameNull?Type
------------------------------------------------------------
TRANSACTION_IDNOT NULLVARCHAR2 (6)
BORROWED_DATEVARCHAR2 (50)
DUE_DATEDATE
BOOK_IDDATE
MEMBER_IDVARCHAR2 (6)
You want to display the member IDs, due date, and late fee as $2 for all transactions.
Which SQL statement must you execute?
- A. SELECT member_id AS "MEMBER ID", due_date AS "DUE DATE", $2 AS "LATE FEE" FROM BOOKS_TRANSACTIONS;
- B. SELECT member_id AS MEMBER_ID, due_date AS DUE_DATE, $2 AS LATE_FEE
FROM BOOKS_TRANSACTIONS; - C. SELECT member_id AS "MEMBER ID", due_date AS "DUE DATE", '$2' AS "LATE FEE" FROM BOOKS_TRANSACTIONS;
- D. SELECT member_id 'MEMBER ID', due_date 'DUE DATE', '$2 AS LATE FEE' FROM BOOKS_TRANSACTIONS;
Answer: C
NEW QUESTION 127
View the exhibit and examine the description of the PRODUCT_INFORMATION table.
Which SQL statement would retrieve from the table the number of products having LIST_PRICE as NULL?
- A. SELECT COUNT (DISTINCT list_price)FROM product_informationWHERE list_price is NULL
- B. SELECT COUNT (list_price)FROM product_informationWHERE list_price is NULL
- C. SELECT COUNT (NVL(list_price, 0))FROM product_informationWHERE list_price is NULL
- D. SELECT COUNT (list_price)FROM product_informationWHERE list_price i= NULL
Answer: C
NEW QUESTION 128
View the exhibit and examine the structures of the EMPLOYEES and DEPARTMENTS tables.
You want to update EMPLOYEES table as follows:
* Update only those employees who work in Boston or Seattle (locations 2900 and 2700).
* Set department_id for these employees to the department_id corresponding to London (location_id
* 2100).
* Set the employees' salary in location_id 2100 to 1.1 times the average salary of their department.
* Set the employees' commission in location_id 2100 to 1.5 times the average commission of their department.
You issue the following command:
What is outcome?
- A. It executes successfully and gives the desired update.
- B. It generates an error because multiple columns (SALARY, COMMISSION) cannot be specified together in an UPDATE statement.
- C. It generates an error because a subquery cannot have a join condition in a UPDATE statement.
- D. It executes successfully but does not give the desired update.
Answer: D
NEW QUESTION 129
Examine this query:
SELECT TRUNC (ROUND(156.00,-2),-1) FROM DUAL; What is the result?
- A. 0
- B. 1
- C. 2
- D. 3
- E. 4
Answer: B
NEW QUESTION 130
View the Exhibits and examine the structure of the costs and promotions tables.
You want to display prod_ids whose promotion cost is less than the highest cost PR0D_ID in a promotion time interval.
Examine this SQL statement:
What will be the result?
- A. It gives an error because the all keyword is not valid.
- B. It executes successfully and gives the required result.
- C. It executes successfully but does not give the required result.
- D. It gives an error because the ROUP BY clause is not valid.
Answer: B
NEW QUESTION 131
Examine the structure of the BOOKS_ TRANSACTIONS table:
Examine the SQL statement:
Which statement is true about the outcome?
- A. It displays details only for members who have borrowed before today with RM as TRANSACTION_TYPE.
- B. It displays details for members who have borrowed before today's date with either RM as TRANSACTION_TYPE or MEMBER_ID as A101 and A102.
- C. It displays details for only members A101and A102 who have borrowed before today with RM as TRANSACTION_TYPE.
- D. It displays details for members who have borrowed before today with RM as TRANSACTION_TYPE and the details for members A101 or A102.
Answer: A
NEW QUESTION 132
In the EMPLOYEES table there are 1000 rows and employees are working in the company for more than 10 years.
Evaluate the following SQL statement:
What would be the result?
- A. It gives an error because multiple NVL functions are used in an expression.
- B. It gives an error because NVL function cannot be used with UPDATE.
- C. It executes successfully but no rows updated.
- D. It executes successfully and updates the records of those employees who have been working in the company for more than 600 days.
Answer: D
NEW QUESTION 133
Examine the description of the BOOKS table:
The table has 100 rows.
Examine this sequence of statements issued in a new session;
INSERT INTO BOOKS VALUES ('ADV112' , 'Adventures of Tom Sawyer', NULL, NULL);
SAVEPOINT a;
DELETE from books;
ROLLBACK TO SAVEPOINT a;
ROLLBACK;
Which two statements are true?
- A. The second ROLLBACK command does nothing.
- B. The first ROLLBACK command restores the 101 rows that were deleted and commits the inserted row.
- C. The first ROLLBACK command restores the 101 rows that were deleted, leaving the inserted row still to be committed.
- D. The second ROLLBACK command replays the delete.
- E. The second ROLLBACK command undoes the insert.
Answer: C,E
NEW QUESTION 134
View the exhibit for the structure of the STUDENTand FACULTYtables.
You need to display the faculty name followed by the number of students handled by the faculty at the base location.
Examine the following two SQL statements:
Statement 1
SQL>SELECT faculty_name, COUNT(student_id)
FROM student JOIN faculty
USING (faculty_id, location_id)
GROUP BY faculty_name;
Statement 2
SQL>SELECT faculty_name, COUNT(student_id)
FROM student NATURAL JOIN faculty
GROUP BY faculty_name;
Which statement is true regarding the outcome?
- A. Both statements 1 and 2 execute successfully and give the same required result.
- B. Only statement 2 executes successfully and gives the required result.
- C. Both statements 1 and 2 execute successfully and give different results.
- D. Only statement 1 executes successfully and gives the required result.
Answer: D
NEW QUESTION 135
Which three statements are true about indexes and their administration in an Oracle database?
- A. A DROP INDEX statement always prevents updates to the table during the drop operation
- B. If a query filters on an indexed column then it will always be used during execution of the query
- C. An index can be created as part of a CREATE TABLE statement.
- D. A UNIQUE and non-unique index can be created on the same table column
- E. A descending index is a type of function-based index
- F. An INVISIBLE index is not maintained when Data Manipulation Language (DML) is performed on its underlying table.
Answer: A,C,E
NEW QUESTION 136
Which three statements are true about performing DML operations on a view with no INSTEAD OF triggers defined?
- A. Insert statements can always be done on a table through a view.
- B. The WITH CHECK clause has no effect when deleting rows from the underlying table through the view.
- C. Views cannot be used to add rows to an underlying table If the table has columns with NOT NULL constraints lacking default values which are not referenced in the defining query of the view.
- D. Views cannot be used to query rows from an underlying table if the table has a PRIMARY KEY and the primary key columns are not referenced in the defining query of the view.
- E. Views cannot be used to add or modify rows in an underlying table If the defining query of the view contains the DISTINCT keyword.
- F. Delete statements can always be done on a table through a view.
Answer: C,D,E
NEW QUESTION 137
View the exhibit and examine the ORDERStable.
The ORDERStable contains data and all orders have been assigned a customer ID. Which statement would add a NOTNULLconstraint to the CUSTOMER_IDcolumn?
ALTER TABLE orders
- A. ADD CONSTRAINT orders_cust_id_nn NOT NULL (customer_id);
ALTER TABLE orders - B. ADD customer_id NUMBER(6)CONSTRAINT orders_cust_id_nn NOT NULL;
- C. MODIFY CONSTRAINT orders_cust_id_nn NOT NULL (customer_id);
ALTER TABLE orders - D. MODIFY customer_id CONSTRAINT orders_cust_nn NOT NULL (customer_id);
ALTER TABLE orders
Answer: D
NEW QUESTION 138
Examine these statements which execute successfully:
ALTER SESSION SET NLS_DATE_FORMAT = 'DD-MON-YYY HH24 :MT:SS;'
ALTER SESSION SET TIME-ZONE = '-5:00;:
Examine the result:
If LOCALTIMESTAMP was selected at the same time, what would it return?
- A. 11-JUL_2019 6.00.00.00000000 AM -05:00
- B. 11-JUL-2019 11.00.00.00000000 AM
- C. 11-JUL-2019 6.00.00.00000000 AM
- D. 11-JUL_2019 11.00.00.00000000 AM -05:00
Answer: C
NEW QUESTION 139
Which three statements are true? (Choose three.)
- A. The usernames of all users including database administrators are stored in the data dictionary.
- B. The USER_CONS_COLUMNS view should be queried to find the names of columns to which constraints apply.
- C. Data dictionary views consist of joins of dictionary base tables and user-defined tables.
- D. Views with the same name but different prefixes, such as DBA, ALL and USER, reference the same base tables from the data dictionary.
- E. Both USER_OBJECTS and CAT views provide the same information about all objects that are owned by the user.
- F. The data dictionary is created and maintained by the database administrator.
Answer: A,B,D
Explanation:
References:
https://docs.oracle.com/cd/B10501_01/server.920/a96524/c05dicti.htm
NEW QUESTION 140
Which three statements are true regarding the data types? (Choose three.)
- A. A TIMESTAMPdata type column stores only time values with fractional seconds.
- B. The value for a CHARdata type column is blank-padded to the maximum defined column width.
- C. Only one LONGcolumn can be used per table.
- D. The BLOBdata type column is used to store binary data in an operating system file.
- E. The minimum column width that can be specified for a VARCHAR2data type column is one.
Answer: B,C,E
NEW QUESTION 141
View the exhibit and examine the description of the PRODUCT_INFORMATIONtable.
Which SQL statement would retrieve from the table the number of products having LIST_PRICEas NULL?
- A. SELECT COUNT (NVL(list_price, 0))
FROM product_information
WHERE list_price is NULL - B. SELECT COUNT (list_price)
FROM product_information
WHERE list_price is NULL - C. SELECT COUNT (DISTINCT list_price)
FROM product_information
WHERE list_price is NULL - D. SELECT COUNT (list_price)
FROM product_information
WHERE list_price i= NULL
Answer: A
NEW QUESTION 142
View the exhibit and examine the description of the DEPARTMENTS and EMPLOYEES tables.
The retrieve data for all the employees for their EMPLOYEE_ID, FIRST_NAME, and DEPARTMENT NAME, the following SQL statement was written:
SELECT employee_id, first_name, department_name
FROM employees
NATURAL JOIN departments;
The desired output is not obtained after executing the above SQL statement. What could be the reason for this?
- A. The NATURAL JOIN clause is missing the USING clause.
- B. The table prefix is missing for the column names in the SELECT clause.
- C. The EMPLOYEES and DEPARTMENTS tables have more than one column with the same column name and data type.
- D. The DEPARTMENTS table is not used before the EMPLOYEES table in the FROM clause.
Answer: C
Explanation:
Natural join needs only one column to be the same in each table. The EMPLOYEES and DEPARTMENTS tables have two columns that are the same (Department_ID and Manager_ID)
NEW QUESTION 143
Which statement is true regarding external tables?
- A. The CREATE TABLE AS SELECT statement can be used to upload data into a normal table in the database from an external table.
- B. The default REJECT LIMIT for external tables is UNLIMITED.
- C. ORACLE_LOADER and ORACLE_DATAPUMP have exactly the same functionality when used with an external table.
- D. The data and metadata for an external table are stored outside the database.
Answer: A
Explanation:
https://docs.oracle.com/cd/B28359_01/server.111/b28310/tables013.htm
NEW QUESTION 144
Examine the commands used to create DEPARTMENT_DETAILS and
COURSE_DETAILS:
You want to generate a report that shows all course IDs irrespective of whether they have corresponding department IDs or not but no department IDs if they do not have any courses.
Which SQL statement must you use?
- A. SELECT c.course_id, d.department_id FROM course_details c RIGHT OUTER JOIN
.department_details d ON (c.depatrment_id=d.department_id) - B. SELECT c.course_id, d.department_id FROM course_details c FULL OUTER JOIN department_details d ON (c.department_id=d. department_id)
- C. SELECT c.course_id, d.department_id FROM course_details c FULL OUTER JOIN department_details d ON (c.department_id<>d. department_id)
- D. SELECT course_id, department_id, FROM department_details d RIGHT OUTER JOIN course_details c USING (department_id)
Answer: B
NEW QUESTION 145
Which statement is true regarding external tables?
- A. The CREATE TABLE AS SELECT statement can be used to upload data into a normal table in the database from an external table.
- B. The default REJECT LIMIT for external tables is UNLIMITED.
- C. ORACLE_LOADER and ORACLE_DATAPUMP have exactly the same functionality when used with an external table.
- D. The data and metadata for an external table are stored outside the database.
Answer: A
Explanation:
Explanation
https://docs.oracle.com/cd/B28359_01/server.111/b28310/tables013.htm
NEW QUESTION 146
Examine the structure of the EMPLOYEES table.
You must display the details of employees who have manager with MANAGER_ID 100, who were hired in the past 6 months and who have salaries greater than 10000.
Which query would retrieve the required result?
- A. SELECT last_name, hire_date, salary
FROM employees
WHERE salary > 10000
UNION ALL
SELECT last_name, hire_date, salary
FROM employees
WHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100) INTERSECT SELECT last_name, hire_date, salary FROM employees WHERE hire_date > SYSDATE- 180; - B. SELECT last_name, hire_date, salary
FROM employees
WHERE manager_id = (SELECT employee_id FROM employees WHERE employee_id = '100') UNION SELECT last_name, hire_date, salary FROM employees WHERE hire_date > SYSDATE -180 INTERSECT SELECT last_name, hire_date, salary FROM employees WHERE salary > 10000; - C. (SELECT last_name, hire_date, salary
FROM employees
WHERE salary > 10000
UNION ALL
SELECT last_name, hire_date, salary
FROM employees
WHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100)) UNION SELECT last_name, hire_date, salary FROM employees WHERE hire_date > SYSDATE -180; - D. SELECT last_name, hire_date, salary
FROM employees
WHERE manager_id = (SELECT employee_id FROM employees WHERE employee_id = 100) UNION ALL (SELECT last_name, hire_date, salary FROM employees WHERE hire_date > SYSDATE -180 INTERSECT SELECT last_name, hire_date, salary FROM employees WHERE salary > 10000);
Answer: B
NEW QUESTION 147
......
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